Question

If a projectile is shot at a velocity of `1 m/s` and an angle of `pi/4`, how far will the projectile travel before landing?

Answer 1

Distance travelled horizontally by a projectile i.e the range of a projectile is expressed as `R=(u^2 sin 2 theta)/g` where, `u` is the velocity of projection and `theta` is the angle of projection.

Given, `u=1 ms^-1,theta=45^@`

So,`R=(1^2 ×1)/g=0.102m`