How do you multiply #(2x - 6) ( 8x - 3)#?

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Answer 1 · 2018-03-04T23:20:46

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2x) - color(red)(6))(color(blue)(8x) - color(blue)(3))# becomes:

#(color(red)(2x) xx color(blue)(8x)) - (color(red)(2x) xx color(blue)(3)) - (color(red)(6) xx color(blue)(8x)) + (color(red)(6) xx color(blue)(3))#

#16x^2 - 6x - 48x + 18#

We can now combine like terms:

#16x^2 + (-6 - 48)x + 18#

#16x^2 + (-54)x + 18#

#16x^2 -54x + 18#