How do you solve #7x+1<4(x-2)#?

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Answer 1 · 2018-03-05T02:36:06

#\text{Interval Notation:}\ \ \ =\ \ \ (-\infty , -3)#
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# #
#7x+1< 4(x−2) #

The first step is to simplify the both sides of inequality.

Distribute the parantheses on the right hand side side by applying the distributive property#\ \ \ a(b+c)=ab+ac\ \ \ # as:

#7x+1<4x-8#

Collect terms involving the variable on left hand side.

#7x+1-1<4x-8-1#

#7x<4x-9#

#7x-4x<4x-9-4x#

#3x<-9#

#\frac{3x}{3}<\frac{-9}{3}#

#x<-3#

# #

That's it!