How do you solve #|3z - 9| = 5#?

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Answer 1 · 2018-03-06T05:29:33

#z=14/3, 4/3#

#|3z-9|=5#
break the absolute value or modulus into positive and negative components, i.e.

#3z-9=5# and #-(3z-9)=5#

#3z-9=5#

#3z=14#

#z=14/3#

and
#-(3z-9)=5#

#3z-9=-5#

#3z=4#

#z=4/3#