How do you solve #144=12f#?

1 Answer
Mar 6, 2018

See a solution process below:

Explanation:

Divide each side of the equation by #color(red)(12)# to solve for #f# while keeping the equation balanced:

#144/color(red)(12) = (12f)/color(red)(12)#

#12 = (color(red)(cancel(color(black)(12)))f)/cancel(color(red)(12))#

#12 = f#

#f = 12#