Question

How do you divide `(2k^3-13k^2-77k+60)div(k-10)` using synthetic division?

Answer 1

Quotient is `2k^2+7k-7` and remainder is `-10`

Explanation:

`2k^3-13k^2-77k+60`

=`2k^3-20k^2+7k^2-70k-7k+70-10`

=`2k^2*(k-10)+7k*(k-10)-7*(k-10)-10`

=`(2k^2+7k-7)*(k-10)-10`

Hence quotient is `2k^2+7k-7` and remainder is `-10`