If Earth has a mass of 5.972 × 10^24 kg and Mars has a mass of 6.39 × 10^23 kg, and the distance between them is 225 x 10^6 m, with what force does Earth pull on Mars?

1 Answer

This is an application of the Universal Gravitation Equation #F_G=G{m_1m_2}/d^2#

Explanation:

In your case, you are given all the variable and all you need to know is that the Gravitational Constant, #G = 6.67xx10^{-11} {m^3}/{kg*s^2}#

So, #F_G=6.67xx10^{-11}{5.972xx10^24*6.3xx10^23}/{(225xx10^6)^2}#

Then, #F_G=6.67xx10^{-11}{3.82xx10^48}/{(50625xx10^12)}#

#F_G=6.67xx10^{-11}{3.82xx10^48}/{(5.06xx10^16)}#

#F_G=6.67xx10^{-11}*7.55xx10^31#

#F_G=5.04xx10^21 #Newtons