How do you find the sum #8+(-6)+2#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Divya Bezawada · EZ as pi Mar 7, 2018 #4# Explanation: #=8+(−6)+2# # =8-6+2# #=4# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 3229 views around the world You can reuse this answer Creative Commons License