What is the moment of inertia of a pendulum with a mass of #8 kg# that is #5 m# from the pivot?

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Answer 1 · 2018-03-07T08:28:40

I get the moment of inertia as #I=200 \ "kg m"^2#.

Moment of inertia of a simple pendulum is given by

#I=mr^2#

So here, #m=8 \ "kg"#, #r=5 \ "m"#

So, we have

#I=8 \ "kg"*25 \ "m"^2#

#=200 \ "kg m"^2#

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