Question

How do you simplify `\frac { 2a ^ { 2} + 3a - 9} { 4a ^ { 2} - 9}`?

Answer 1

`2a^2 +3a-9=2a^2+6a-3a-9=2a(a+3) -3(a+3)=(a+3)(2a-3)`

And, `4a^2-9=(2a)^2 -3^2=(2a+3)(2a-3)`

So, `(2a^2 +3a-9)/(4a^2-9)=(a+3)/(2a+3)`