Solve for Pressure (Ideal Gas Law)?
Pxx0.21=2.1xx0.0821xx290P×0.21=2.1×0.0821×290
PxxV=nxxRxxTP×V=n×R×T
1 Answer
Mar 8, 2018
You must put units on your equations... if you don't, it won't be clear what you have calculated...
PV = nRTPV=nRT
P = (nRT)/VP=nRTV
= (("2.1 mols ideal gas")("0.0821 L"cdot"atm/mol"cdot"K")("290 K"))/("0.21 L")=(2.1 mols ideal gas)(0.0821 L⋅atm/mol⋅K)(290 K)0.21 L
= ???=???
What must the units of pressure become in this case?