Solve for Pressure (Ideal Gas Law)?

Question

#Pxx0.21=2.1xx0.0821xx290#

#PxxV=nxxRxxT#

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Answer 1 · 2018-03-08T20:15:20

You must put units on your equations... if you don't, it won't be clear what you have calculated...

#PV = nRT#

#P = (nRT)/V#

#= (("2.1 mols ideal gas")("0.0821 L"cdot"atm/mol"cdot"K")("290 K"))/("0.21 L")#

#= ???#

What must the units of pressure become in this case?