Solve for Pressure (Ideal Gas Law)?

Question

#Pxx0.21=2.1xx0.0821xx290#

#PxxV=nxxRxxT#

4148 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-08T20:15:20

You must put units on your equations... if you don't, it won't be clear what you have calculated...

#PV = nRT#

#P = (nRT)/V#

#= (("2.1 mols ideal gas")("0.0821 L"cdot"atm/mol"cdot"K")("290 K"))/("0.21 L")#

#= ???#

What must the units of pressure become in this case?