3+x=square root of 6x+13?

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Answer 1 · 2018-03-09T15:51:59

#x = +- 2#

#3+x=sqrt (6x+13)#

#(3+x)^2=sqrt (6x+13)^2#

Notice that both sides are greater than zero or equal to zero:

#3 + x ≥ 0 and 6x + 13 ≥ 0 => x ≥ -13/6#
If #x < -13/6,# x won't work in the original equation.

#9 + 6x + x^2 =6x+13#

#x^2 = 4#

#x = +- 2 # and both works in the original equation.