3+x=square root of 6x+13?

1 Answer
Mar 9, 2018

#x = +- 2#

Explanation:

#3+x=sqrt (6x+13)#

#(3+x)^2=sqrt (6x+13)^2#

Notice that both sides are greater than zero or equal to zero:

#3 + x ≥ 0 and 6x + 13 ≥ 0 => x ≥ -13/6#
If #x < -13/6,# x won't work in the original equation.

#9 + 6x + x^2 =6x+13#

#x^2 = 4#

#x = +- 2 # and both works in the original equation.