#y=-1/2x+9 and y=x+7# what is solution for this system of equations?

1 Answer
Mar 9, 2018

#(x,y)=(4/3,25/3)#

Explanation:

Given:
#y=-1/2x+9" ".....................Equation(1)#
#y=color(white)("dddd")x+7" "......................Equation(2)#

#color(blue)("Determine the value of "y)#

#2y=-x+18 color(white)("dd")larr 2xx Equation(1) #
#ul(color(white)("d")y=color(white)("dd")x+7color(white)("ddd") larr" Equation(2))#
#3y = 0 +25 larr" Added"#

Divide both sides by 3

#y=25/3#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Determine the value of "x)#

Substitute for #y# in #Equation(2) larr# most straight forward

#y=x+7color(white)("ddd") -> color(white)("ddd")25/3=x+7#

Subtract 7 from both sides

#4/3=x# Write this as per convention

#x=4/3#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(blue)("The point shared by the two plots (solution) is:")#

#(x,y)=(4/3,25/3)#

Tony B