How do you solve #2(x-3)=(x-1)+7#?

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Answer 1 · 2018-03-09T23:05:52

#x=12#

#2(x-3)=(x-1)+7#

Distribute the left side

#(2)(x)+(2)(-3)=x-1+7#

#2x - 6 = x + 6#

Subtract #x# on both sides

#2x - 6 - x = cancelx + 6 cancel(-x)#

#x - 6 = 6#

Finally, add #6# on both sides

#x cancel(-6) cancel(+6) = 6+6#

#x=12#