How do you solve #15( 6c - 1) - 4= 88c + 15#?

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Answer 1 · 2018-03-09T23:47:32

#c=17#

#15(6c-1)-4=88c+15#

Distribute

#(15)(16c)+(15)(-1)-4=88c=15#

#90c - 15 - 4 =88c +15#

#90c - 19 = 88c + 15#

Add #color(red)(19)# to both sides

#90c cancel(-19) cancelcolor(red)(+19)= 88c + 15 + color(red)(19)#

#90c = 88c + 34#

Subtract #color(green)(88c)# from both sides

#90c - color(green)(88c)= cancel(88c) + 34 cancelcolor(green)(-88c)#

#2c = 34#

Then divide both sides by #color(purple)(2)#

#(cancel2c)/cancelcolor(purple)(2)=34/color(purple)(2)#

#c=17#