How do you solve #128- w = 203#?

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Answer 1 · 2018-03-10T00:41:19

The solution is #w=-75#.

Isolate #w# by adding #w# to both sides of the equation then subtracting #203#:

# 128-w=203 #

# 128-wcolor(blue)+color(blue)w=203color(blue)+color(blue)w #

# 128color(red)cancelcolor(black)(-wcolor(blue)+color(blue)w)=203color(blue)+color(blue)w #

# 128=203+w #

# 128color(blue)-color(blue)203=203+wcolor(blue)-color(blue)203 #

# 128color(blue)-color(blue)203=203color(blue)-color(blue)203+w #

# 128color(blue)-color(blue)203=color(red)cancelcolor(black)(203color(blue)-color(blue)203)+w #

# 128-203=w #

# -75=w #

# w=-75 #