How do you solve #5w ^ { 2} + 28w = - 32#?

1 Answer
Nityananda
Mar 10, 2018

w = - 4 or - 8/5

Explanation:

Given, #5w^2+28w = -32#
#rArr 5w^2+28w+32=0#
#rArr 5w^2+(20+8)w+32=0#
#rArr 5w^2+20w+8w+32=0#
#rArr 5w(w+4)+8(w+4)=0#
#rArr (w+4)(5w+8)=0#
#rArr (w+4)=0,(5w+8)=0#
#rArr w = -4, w =-8/5#
#rArr w = -4 or -8/5#

Related questions
Impact of this question
1068 views around the world
You can reuse this answer
Creative Commons License