How do you simplify #\frac { 7x ^ { 2} y ^ { 6} } { 14x ^ { 2} y ^ { 3} }#?

1 Answer
Mar 11, 2018

See a solution process below:

Explanation:

First, cancel common terms in the numerator and denominator:

#(color(red)(cancel(color(black)(7)))1color(blue)(cancel(color(black)(x)))y^6)/(color(red)(cancel(color(black)(7)))2color(blue)(cancel(color(black)(x)))y^3) => y^6/(2y^3)#

Then use this rule for exponents to simplify the #y# term:

#x^color(red)(a)/x^color(blue)(b) = x^(color(red)(a)-color(blue)(b))#

#y^color(red)(6)/(2y^color(blue)(3)) => y^(color(red)(6)-color(blue)(3))/2 => y^3/2#

Or

#1/2y^3#