How do you solve #2= 11+ 3( m + 3) #?

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Answer 1 · 2018-03-11T14:33:31

#m=-6#

#2 = 11 + 3m + 9#

#3m = 2 - 11 - 9#

#3m = -18#

#m = -6#

Answer 2 · 2018-03-11T14:54:23

#m=-6#

#2 = 11 + 3(m +3)#

Start by distributing

#2 = 11 + (3)(m)+(3)(3)#

#2 = 11 + 3m + 9#

#2 = 3m + 20#

Then flip the equation

#3m + 20 = 2#

Subtract #20# on both sides

#3m + 20 - 20 = 2 - 20#

#3m = -18#

Divide both sides by #3#

#(cancel3m)/cancel3 = (-18)/3#

#m=-6#