Question

I really need an answer, I was absent the day this was discuss and I don't know what to do here please ASAP Annie is 8 years older than Girlie. Two years ago, Annie was twice as old as Girlie. What are their present ages?

I get the first part, which is x-y=8 , but I don't get the other, I multiplied girlie's age bt two and subtract both age by 2 , then what?

Answer 1

Girlie is 10, Annie is 18

Explanation:

Let Girlie's age be `y`
and Annie's age be `x`

You have correctly found that `x=y+8 or x-y=8`

The second statement tells us that
two years ago `2y=x`

Hence we solve the equations simultaneously (I have done it by substitution) to find their ages two years ago, then simply add 2 to each of their ages.

`=> 2y=y+8`
`=> y=8`
`=> x=2*8 = 16`

then add two to each:
`y=10`
`x=18`

Alt method:
If you are confident rearranging equations,
equation 2 can be written as: `2(y-2)=(x-2)`
which removes the need to add two later.

`2(y-2)=(y+8-2)`
`=> 2y-4=y+6`
`=>y=10`
`=> x=10+8=18`