Is #f(x)=(x-2)^2(x+1)# increasing or decreasing at #x=1#?
1 Answer
Mar 11, 2018
Explanation:
#"to determine if f(x) is increasing/decreasing at x = 1"#
#"differentiate f(x) and evaluate at x = 1"#
#• " if "f'(1)>0" then "f(x)" is increasing at x = 1"#
#• " if "f'(1)<0" then "f(x)" is decreasing at x = 1"#
#f(x)=(x-2)^2(x+1)larrcolor(blue)"expand factors"#
#color(white)(f(x))=x^3-3x^2+4#
#rArrf'(x)=3x^2-6x#
#rArrf'(1)=3-6=-3<0#
#"since" 'f'(1)<0" then "f(x)" is decreasing at x = 1"#
graph{(x-2)^2(x+1) [-10, 10, -5, 5]}