How do you solve #4f - 5+ 6= 35#?

1 Answer
Mar 12, 2018

See a solution process below:

Explanation:

First, combine like terms on the left side of the equation:

#4f - color(red)(5) + color(red)(6) = 35#

#4f + 1 = 35#

Next, subtract #color(red)(1)# from each side of the equation to isolate the #f# term while keeping the equation balanced:

#4f + 1 - color(red)(1) = 35 - color(red)(1)#

#4f + 0 = 34#

#4f = 34#

Now, divide each side of the equation by #color(red)(4)# to solve for #f# while keeping the equation balanced:

#(4f)/color(red)(4) = 34/color(red)(4)#

#(color(red)(cancel(color(black)(4)))f)/cancel(color(red)(4)) = (color(red)(cancel(color(black)(34)))17)/color(red)(color(black)(cancel(color(red)(4)))2)#

#f = 17/2#