Differentiate with respect to x 1+1/x² ?

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Answer 1 · 2018-03-13T01:18:06

$f'(x) = -2/x^3$

$f(x) = 1+1/x^2$

$(df(x))/(dx) = d/(dx)(1) + d/(dx)1/x^2$

$f'(x) = 0 -2/x^3$

$f'(x) = -2/x^3$

Answer 2 · 2018-03-13T01:21:53

$-2/x^3$

$=d/dx(1+1/x^2)$
$=d/dx(1+x^-2)$
$=-2x^-3$
$=-2/x^3$