What is the value of #h(-3)# if #h(x)=x^2-x#?

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Answer 1 · 2018-03-13T18:40:58

12

#h(-3)=(-3)^2-(-3)#
#h(-3)=9+3=12#

Answer 2 · 2018-03-13T18:41:54

#h(-3) = 12 #

#h(x) = x^2 -x #

For a function, if you were trying to find #h(-3) # you'd simply replace every #x# you see with #-3 #

#=> h(-3) = (-3)^2 - ( -3 ) #

#= 9 +3 = 12 #