A ball with a mass of #1 kg# moving at #1 m/s# hits a still ball with a mass of #8 kg#. If the first ball stops moving, how fast is the second ball moving?

Question

1559 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-13T19:07:14

The velocity of the second ball after the collision is #=0.125ms^-1#

#m_1u_1+m_2u_2=m_1v_1+m_2v_2#

The mass the first ball is #m_1=1kg#

The velocity of the first ball before the collision is #u_1=1ms^-1#

The mass of the second ball is #m_2=8kg#

The velocity of the second ball before the collision is #u_2=0ms^-1#

The velocity of the first ball after the collision is #v_1=0ms^-1#

Therefore,

#1*1+8*0=1*0+8*v_2#

#8v_2=1#

#v_2=1/8=0.125ms^-1#

The velocity of the second ball after the collision is #v_2=0.125ms^-1#