Question

How do you solve `10+ 5x = 110`?

Answer 1

`10+5x=110`
`5x+10-10=110-10`
`5x=100`
`(5x)/5=100/5`
`x=20`

Answer 2

`x=20`

Explanation:

First subtract 10 from both sides.
`5x=100`
Then, divide both sides by 5
`x=20`

Answer 3

The trick is to get x by itself by moving the other numbers around... That way you find that x=20.

Explanation:

In order to get our solution, we will work this in two steps:

1. Move all terms, other than x and its coefficient, to the right-hand side
2. Divide both sides by x's coefficient to get x alone

Step 1:
For this, we will subtract 10 from both sides. This will remove the 10 from the left hand side, and remove the same amount from the right hand side.

`cancel(10)+5x-cancel(10)=110-10 rArr 5x=100`

Step 2:
Now that we've moved everything else to the right hand side, we can divide both sides by x's coefficient. In this case, we will divide by 5:

`(cancel(5)x)/cancel(5)=100/5 rArr x=100/5`

Now we solve the division and get our answer:
`x=100/5 rArr color(red)(x=20)`

Answer 4

`x = 20`

Explanation:

Isolate the `x` term to one side so that we can solve for it:

Subtract 10 from both sides:
`10+5x=110`
`color(blue)"-10 " " " " "` `color(blue)"-10"`
`------`
`5x = 100`

Now divide by `5` to isolate `x` by itself:
`(cancel5x)/cancel5 = 100/5`
`x = 20`