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Question

$evaluate (3/3)$ in factorial form

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Answer 1 · 2018-03-13T22:47:39

$((3),(3))=(3!)/(3!(3-3)!)$

Assuming you meant $((3),(3))$ , this is another way to write $3C3$ .

Also called a combination, $nCr=(n!)/(r!(n-r)!)$

Here, $n=3$ and $r=3$ .

Therefore, $((3),(3))=(3!)/(3!(3-3)!)$

Just in case you're curious about what this is equal to:

$=>(3!)/(3!(3-3)!)$

$=>(3!)/(3!(0)!)$

$=>(cancel(3!))/(cancel(3!)*1)$

$=>1$