Question

What is the moment of inertia of a rod with a mass of `6 kg` and length of `5 m` that is spinning around its center?

Answer 1

`I = 12.5 \text( kg m)^2`

Explanation:

Moment of inertia of rod with rotational axis about its center is given as:

`I = 1/12 ml^2`

We are given `m = 6` kg and `l = 5` m.

`I = 1/12 (6)(5)^2 = 12.5 \text( kg m)^2`