Evaluate $\sqrt{6} - \sqrt{3}$ $sqrt(6)-sqrt(3)$ when $\sqrt{2} = 1.414$ $sqrt(2)=1.414$ ?

Question

Evaluate $\sqrt{6} - \sqrt{3}$ $sqrt(6)-sqrt(3)$ when $\sqrt{2} = 1.414$ $sqrt(2)=1.414$ ?

2 Answers

Impact of this question

6104 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-14T03:38:43

$0.414 \sqrt{3}$ $0.414sqrt3$
or
$0.717$ $0.717$

Explanation:

$\sqrt{6} - \sqrt{3}$ $sqrt6-sqrt3$

$= \sqrt{2} \sqrt{3} - \sqrt{3}$ $=sqrt2sqrt3-sqrt3$

$= \sqrt{3} (\sqrt{2} - 1)$ $=sqrt3(sqrt2-1)$

$= \sqrt{3} (1.414 - 1)$ $=sqrt3(1.414-1)$

$= 0.414 \sqrt{3}$ $=0.414sqrt3$

Note: $\sqrt{3} \approx 1.732$ $sqrt3 approx 1.732$
Therefore,

$\sqrt{6} - \sqrt{3}$ $sqrt6-sqrt3$

$= 0.414 (1.732)$ $=0.414(1.732)$

$= 0.717$ $=0.717$

Answer 2 · 2018-03-14T03:38:46

$\sqrt{6} - \sqrt{3} = 0.414 \sqrt{3}$ $sqrt6-sqrt3=color(blue)(0.414sqrt3$

Explanation:

Given:

$\sqrt{6} - \sqrt{3}$ $sqrt6-sqrt3$

Prime factorize $\sqrt{6}$ $sqrt6$ .

$\sqrt{2 \times 3} - \sqrt{3}$ $sqrt(2xx3)-sqrt3$

Apply rule: $\sqrt{a b} = \sqrt{a} \sqrt{b}$ $sqrt(ab)=sqrt(a)sqrt(b)$

$\sqrt{2} \sqrt{3} - \sqrt{3}$ $sqrt2sqrt3-sqrt3$

Substitute $1.414$ $1.414$ for $\sqrt{2}$ $sqrt2$ .

$1.414 \sqrt{3} - \sqrt{3}$ $1.414sqrt3-sqrt3$

The coefficient of $\sqrt{3}$ $sqrt3$ is understood to be $1$ $1$ .

$\sqrt{3} = 1 \times \sqrt{3}$ $sqrt3=1xxsqrt3$

$1.414 \sqrt{3} - 1 \sqrt{3}$ $1.414sqrt3-1sqrt3$

$0.414 \sqrt{3}$ $0.414sqrt3$

Science

Math

Humanities

... and beyond

Evaluate $\sqrt{6} - \sqrt{3}$ $sqrt(6)-sqrt(3)$ when $\sqrt{2} = 1.414$ $sqrt(2)=1.414$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

Evaluate √6−√3sqrt(6)-sqrt(3) when √2=1.414sqrt(2)=1.414 ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Evaluate $\sqrt{6} - \sqrt{3}$ $sqrt(6)-sqrt(3)$ when $\sqrt{2} = 1.414$ $sqrt(2)=1.414$ ?