How do you subtract #(4x+5)/(5x-2)-(3x-7)/(5x-2)#?

1 Answer
Mar 14, 2018

#(4x+5)/(5x-2)-(3x-7)/(5x-2)=(x+12)/(5x-2)#

Explanation:

Here the denominator is the same. So, write the denominator as one term and then subtract the numerator.

#(4x+5)/(5x-2)-(3x-7)/(5x-2)=((4x+5)-(3x-7))/(5x-2)#
#=(4x+5-3x+7)/(5x-2)# [Distrubution property]
#=(x+12)/(5x-2)# [Adding like terms]