What are the asymptotes and removable discontinuities, if any, of #f(x)= 1/x^2+2#?

1 Answer
Mar 14, 2018

Vertical Asymptote: #x=0#
Horizontal Asymptote: #y=0#

Explanation:

You can find a vertical asymptote
when you set the denominator equal to 0.

#x^2=0#
#x=0#
Therefore the vertical asymptote is 0.

Horizontal asymptote happens when the denominator has a higher degree or equal degree to the numerator. In this case the denominator has a higher degree then the numerator, so the is the horizontal asymptote is 0.