Zn(s) + 2AgNO3 ---> 2Ag (s) + Zn(NO3)2 When an excess of Zn reacts with 25.00 g of AgNO3, (1.43x10^1) grams of silver are produced. What is the percent yield?

1 Answer
Hriman
Mar 15, 2018

#90.1%#

Explanation:

Step 1: Theoretical yield
#25 cancel("g AgNO"_3)* (1cancel("mol AgNO"_3))/ (169.87 cancel("g AgNO"_3)) * (2 cancel("mol Ag"))/ (2 cancel("mol AgNO"_3))* (107.87 "g Ag")/ (1 cancel("mol Ag"))=#
#15.88 "g Ag"#

Step 2: percent yield:
Experimental/Theoritical*100=
#(14.3g)/ (15.88 g)*100= 90.1%#

A very high percent yield in my opinion

Related questions
Impact of this question
3890 views around the world
You can reuse this answer
Creative Commons License