What is the vertex of the graph #f(x)=x^2-6x+7#?

Question

3560 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-15T22:04:14

Given the equation of a parabola of the form #f(x) = ax^2+bx+c# the x-coordinate of the vertex is:

#h=-b/(2a)#

The y-coordinate of the vertex is:

#k=ah^2+bh+c#

Given: #f(x)=x^2-6x+7#

We observe that #a = 1, b = -6 and c = 7#

The x-coordinate of the vertex is:

#h = - (-6)/(2(1))#

#h = 3#

The y-coordinate of the vertex is:

#k = 3^2-6(3)+7#

#k = -2#

The vertex is #(3,-2)#