Question

A rectangular lot has to be fenced with chicken wire. the chicken wire needed is 96cm. what is the dimension of the lot if the length is twice its width? Hint:(P=21+2w)

i really cant understand if it is word problem pls helpp

Answer 1

System of equations, see below

Dimensions: `16 "cm" xx 32"cm"`

Explanation:

We will be solving with substitution.
The perimeter is `96 "cm"`, because that's the amount of fencing needed to cover the lot.

So we can say that:
`2l+2w=96`
where `l` is the length and `w` is the width.

We are also told that length is twice its width:
`l=2w`

We will now solve for the width by substitution by plugging in `2w` for `l` in the first equation:
`2(2w)+2w=96`
`4w+2w=96`
`6w=96`
`\color(green)(w=16 "cm")`

Now to find the length, substitute the width into the second equation:
`l= 2(16)`
`\color(green)(l= 32 "cm")`