How do you solve #5abs(2x + 1 ) = 55#?

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Answer 1 · 2018-03-16T04:10:40

#x=-6,5#

We got: #5|2x+1|=55#

Dividing both sides by #5#, we get

#|2x+1|=55/5#

#=11#

So, #2x+1=+-11#, since #|a|=+-a#.

And so,

#2x+1=11#

#2x=10#

#x=10/2=5#

#2x+1=-11#

#2x=-12#

#x=-12/2=-6#

As you can see, there are two solutions for #x#, and #x\in{-6,5}#.