Question

Sociologists say that 95% of married women claim that their husband's mother is the biggest bone of contention in their marriages. Suppose that six married women are having coffee together. What's the probability none of them dislike their mother-in-law?

Answer 1

0.000000015625

Explanation:

P(disliking mother in law) = 0.95

P(not disliking mother in law) = 1-0.95 = 0.05

P(all 6 are not disliking their mother in law) = P(first one does not dislike mother-in-law) * P(second one) * ... * P(6th one does not dislike their mother in law)

`= 0.05 * 0.05 * 0.05 * 0.05 * 0.05 * 0.05 = 0.05^6 = 0.000000015625`