How do you solve #(2x+10)/3+(x-10)/4= 9/2#?

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Answer 1 · 2018-03-16T16:46:15

#x=4#

#(2x+10)/3+(x-10)/4=9/2#

#[4*(2x+10)+3*(x-10)]/12=9/2#

#(8x+40+3x-30)/12=9/2#

#11x+10=9/2*12#

#11x+10=54#

#11x=44#

#x=4#