Question

A plane is flying horizontally at 98 M per second and releases an object which reaches the ground in 10 seconds the angle made by 8 while hitting the ground is?

Answer 1

The angle can be find just by finding the vertical component and horizontal component of velocity with which it will hit the ground.

So,considering for vertical motion,velocity after `10s` will be,

`v=0+g t` (as,initially downward component of velocity was zero)

so,`v=9.8*10=98ms^-1`

Now,horizontal component of velocity remains constant through out the motion i.e `98 ms^-1` (as because this velocity was imparted to the object while releasing from the plane moving with this amount of velocity)

So,angle made with the ground while hitting is `tan^-1(98/98)=45^@`