How do you evaluate #7 xx(16/(2^3)) + (5-4)#?

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Answer 1 · 2018-03-18T08:00:34

#15#

There are two terms. Calculate an answer for each separately and then add the answers together at the end.

In each term, simplify the brackets first.

#color(blue)(7xx(16/2^3))" "+" " color(green)(5-4)#

#=color(blue)(7xx(16/8))" "+" " color(green)(1)#

#=color(blue)(7xx2)" "+" " color(green)(1)#

#=color(blue)(14)" "+" " color(green)(1)#

#=15#