How do you simplify #2\sqrt{32}-\sqrt{18}#?

2 Answers
Mar 18, 2018

#5sqrt2#

Explanation:

Let's factorize each of the numbers in the square roots:

#32 = 2 * 2 * 2 * 2 * 2 = 2 * 4^2#
#18 = 2 * 3 * 3 = 2 * 3^2#

So their square roots are
#sqrt32 = 4 * sqrt(2) # and #sqrt18 = 3 * sqrt2#

Therefore,
#2sqrt32 - sqrt18 = 2 * 4 * sqrt2 - 3 * sqrt2 = 5 sqrt2 #

To check numerically, if we plug this into a calculator we get
#2sqrt(32) approx 11.31#, #sqrt18 approx 4.24 #, and #5sqrt2 approx 7.07# and we see that #11.31 - 4.24 = 7.07 # as expected.

Mar 18, 2018

#5sqrt2#

Explanation:

#2sqrt32-sqrt18#

#:.=2sqrt(4*4*2)-sqrt(2*3*3)#

#:.sqrt3*sqrt3=3#

#:.sqrt4*sqrt4=4#

#:.=2*4sqrt2-3sqrt2#

#:.=8sqrt2-3sqrt2#

#:.=5sqrt2#