First, add #9h# to both sides of the equation. Then divide by #f#. It looks like this:
# fg-9h=10j #
# fg-9hcolor(blue)+color(blue)(9h)=10jcolor(blue)+color(blue)(9h) #
# fgcolor(red)cancelcolor(black)(-9hcolor(blue)+color(blue)(9h))=10jcolor(blue)+color(blue)(9h) #
# fg=10j+9h #
# color(blue)(color(black)(fg)/f)=color(blue)(color(black)(10j+9h)/f) #
# color(blue)(color(black)(color(red)cancelcolor(black)fg)/color(red)cancelcolor(black)f)=color(blue)(color(black)(10j+9h)/f) #
# g=color(black)(10j+9h)/f #
That's the answer. Hope this helped!