The function #f(x) = x^2-12x+5# written in vertex form is #f(x) = (x-6)^2-31#. What are the coordinates of the vertex?
1 Answer
Mar 19, 2018
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#
#f(x)=(x-6)^2-31" is in vertex form"#
#rArrcolor(magenta)"vertex "=(6,-31)#