The function #f(x) = x^2-12x+5# written in vertex form is #f(x) = (x-6)^2-31#. What are the coordinates of the vertex?

1 Answer
Mar 19, 2018

#(6,-31)#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#

#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#

#f(x)=(x-6)^2-31" is in vertex form"#

#rArrcolor(magenta)"vertex "=(6,-31)#