How do I solve this limit? #lim_(x->0)((1-cos^3(3x))/(xsin6x))#

I know I have to find a workaround the division by zero, but I just don't see it.

Thanks in advance.

1 Answer
Jim H
Mar 20, 2018

\ See below.

Explanation:

#(1-cos^3(3x))/(xsin(6x)) = ((1-cos(3x)(1+cos(3x)+cos^2(3x))))/(2xsin(3x)cos(3x))#

# = ((1-cos(3x)(1+cos(3x)+cos^2(3x))))/(2xsin(3x)cos(3x)) * (1+cos(3x))/(1+cos(3x))#

# = (sin^2(3x)(1+cos(3x)+cos^2(3x)))/(2xsin(3x)cos(3x)(1+cos(3x))#

# = 3/2(sin(3x)/(3x))(1+cos(3x)+cos^2(3x))/(cos(3x)(1+cos(3x))#

As #xrarr0#, we see the limit is #9/4#

Related questions
Impact of this question
3152 views around the world
You can reuse this answer
Creative Commons License