How do you solve the system of equations #y=5-2x# and #3x-2y=4# by substitution?

1 Answer
Daniel X.
Mar 20, 2018

#x=2# and #y=1#.

Explanation:

Since you know that #y=5-2x#, you substitute it into #3x-2y=4# to get #3x-2(5-2x)=4#. Solving for #x#, you get #3x-10+4x=4#, so #7x-10=4#, and finally #7x=14#, so #x=2# Substituting #x=2# into #y=5-2x# gives us #y=5-2*2=5-4=1#.

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