Question

One year ago, Clare was 4 feet 6 inches tall. Now Clare is 4 feet 10 inches tall. By what percentage did Clare’s height increase in the last year?

Answer 1

Clare's height increased by about 7.4% in the last year.

Explanation:

Convert both measurements to inches.
4 feet 6 inches = 54 inches
4 feet 10 inches = 58 inches

Formula for Percent of Increase:
`% of Increase = "Difference" / "Original" * 100`

`"58 - 54" / "54" * 100`

`"4" / "54" * 100`

`7.407407... %`

or about `7.4%`

Answer 2

See a solution process below:

Explanation:

First, let's convert the measurements into inches:

`4"ft "6"in "= (4 xx 12)"in" + 6"in" = 48"in" + 6"in" = 54"in"`

`4"ft "10"in "= (4 xx 12)"in" + 10"in" = 48"in" + 10"in" = 58"in"`

Now, we can use this formula for calculating the percent change in a value between two points in time is:

`p = (N - O)/O * 100`

Where:

`p` is the percent change - what we are solving for in this problem.

`N` is the New Value - 58 inches in this problem.

`O` is the Old Value - 54 inches in this problem.

Substituting and solving for `p` gives:

`p = (58"in" - 54"in")/(54"in") * 100`

`p = (4color(red)(cancel(color(black)("in"))))/(54color(red)(cancel(color(black)("in")))) * 100`

`p = 400/54`

`p = 7.bar407`

Or

`7.bar407%` change