Question

A fourth harmonic standing wave is set up in a 3 m long guitar string. If the frequency of the wave is 191 Hz, what is its velocity?

Answer 1

If the length of the guitar is `l`,then for `4` th harmonic `lambda =(2l)/4=l/2=3/2=1.5m`

Now,using `v=nulambda`

Given, `nu=191 Hz`

So,`v=191×1.5=286.5 ms^-1`