How do you simplify $2 [3 y - 4 (x + 2)] + 2 (x + y)$ $2[3y-4(x+2)]+ 2(x+y)$ ?

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Answer 1 · 2018-03-21T05:39:27

$- 6 x + 8 y - 16$ $-6x+8y-16$

$2 [3 y - 4 (x + 2)] + 2 (x + y)$ $2[3y-4(x+2)]+2(x+y)$

$= 2 (3 y - 4 x - 8) + 2 x + 2 y$ $=2(3y-4x-8)+2x+2y$

$= 6 y - 8 x - 16 + 2 x + 2 y$ $=6y-8x-16+2x+2y$

$= - 6 x + 8 y - 16$ $=-6x+8y-16$

How do you simplify 2[3y−4(x+2)]+2(x+y)2[3y-4(x+2)]+ 2(x+y)?