Question

How do you graph `16m ^ { 2} - 4m + 8< 0`?

Answer 1

See below.

Explanation:

`f(m) =16m^2-4m+8 <0`

First, we can simplify the inequality by dividing through be 4.

`-> 4m^2-m+2<0`

Now, we will map the variable `m` onto the `x-` axis of the `xy-`plane.

Considering the graph of the limiting case where `f(m) =0`,

graph{4x^2-x+2 [-20.86, 19.66, -3.06, 17.21]}

Then, the area represented by the inequality `f(m)<0` is shown below below.

graph{(4x^2-x+2)-y <0 [-20.86, 19.66, -3.06, 17.21]}