How do you use the remainder theorem to find the remainder of #(x^3 - 5x^2 + 7x +3) ÷ (x-2)#?

1 Answer
Mar 21, 2018

Put 2 as the value of #x# in the dividend

Explanation:

The remainder theorem states that every polynomial,
For Ex - p( #x# )= #x^2 + x + 1#
if divided by a polynomial of the form - ( #x - a# )
will give remainder as p(#a#) = (In this case) #a^2 + a + 1#

Here:
p(#x#) = #(x^3 - 5x^2 + 7x + 3)#
g(#x#) = #(x-2)#

So,
p(#2#) = #(2^3 - 5*2^2 + 7*2 + 3)#
= #(8-20+24 + 3)#
= #15#
Remainder = 15