Question

A 5 gram piece of aluminum foil at 100 degrees C is dropped into a 25 gram container of water at 20 degrees C. What is the final temperature of the aluminum?

Set the energy gained by water equal to the energy lost by aluminum and the sum of the changes in temperature equal to 80 degrees. Solve these two simultaenous equations for change in temperature.

Answer 1

See below

Explanation:

Heat capacity ( heat added or removed) = specfic heat x mass x change in temperature

`Q= c * m * deltat` calories, if mass is gms, temp. change is C

Specific Heat of water is 1
Specific Heat of aluminum is 0.21

Plug in the values and do the math.